用“破圈法”求解带权连通无向图的一棵最小代价生成树

上传者: u011066665 | 上传时间: 2019-12-21 21:21:23 | 文件大小: 1.4MB | 文件类型: zip
我们可用“破圈法”求解带权连通无向图的一棵最小代价生成树。所谓“破圈法”就是“任取一圈,去掉圈上权最大的边”,反复执行这一步骤,直到没有圈为止。请给出用“破圈法”求解给定的带权连通无向图的一棵最小代价生成树的详细算法,并用程序实现你所给出的算法. 这也是复旦大学97年数据结构和操作系统的考研题.答案,亲测可用,c++编写工程。

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