编写一个弹出式菜单的shell程序 实现以下五个操作

#!/bin/sh echo "******************************************************************" echo " * MENU *" echo " * 1.copy 2.rename *" echo " * 3.remove 4.find *" echo " * 5.exit *" echo "*******************************************************************" declare -i i=1 while [ $i -eq 1 ] do echo "Please input a number(1-5):" read num case $num in