基于Java的实例源码-用Java加密类实现DES、RSA及SHA的加密算法.zip
2024-04-17 00:08:07 47KB Java
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成都市医保局加解密方法工具类及调用demo(医保电子处方中心)V1.0
2024-04-16 15:10:23 10.34MB 加密解密 医保接口
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合肥工业大学计算机类C++上机考试题集,计算机专业、软件工程专业等都可以使用,有的老师编程题会在里面出。平时拿来练手也非常不错
2024-04-15 12:11:56 55KB 合肥工业大学 软件工程
NC330-17.75/0.4/540/540 型抽汽凝汽式汽轮机性能计算源代码-python版(包含一类修正二类修正计算) 根据运行参数挨个输入压力、温度、流量、发电机负荷等参数后,即可计算出汽轮机的高中压缸效率、试验热耗率,一类修正后热耗率、二类修正后热耗率,高加上端差、下端差、凝汽器过冷度等性能参数。计算方便准确。
2024-04-15 11:55:36 19KB python
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考试类精品-- ~南京大学计算机系暑期夏令营上机试题(根据博客上收集的题目还原题目并给出自己的解法版本,仅供参考学习)
2024-04-14 16:09:39 13KB
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这是用于使用软边界模型和次梯度下降优化的 2 类问题的支持向量机代码。
2024-04-14 15:15:16 81KB matlab
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2021金融监管/银保监 计算机类真题
2024-04-13 14:32:55 435KB
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package com.map; public class GPSConverterUtils { public static final String BAIDU_LBS_TYPE = "bd09ll"; public static double pi = 3.1415926535897932384626; public static double a = 6378245.0; public static double ee = 0.00669342162296594323; /** * 84 to 火星坐标系 (GCJ-02) World Geodetic System ==> Mars Geodetic System * 天地图 转 火星 * @param lat * @param lon */ public static GPS gps84_To_Gcj02(double lat, double lon) { if (outOfChina(lat, lon)) { return null; } double dLat = transformLat(lon - 105.0, lat - 35.0); double dLon = transformLon(lon - 105.0, lat - 35.0); double radLat = lat / 180.0 * pi; double magic = Math.sin(radLat); magic = 1 - ee * magic * magic; double sqrtMagic = Math.sqrt(magic); dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi); double mgLat = lat + dLat; double mgLon = lon + dLon; return new GPS(mgLat, mgLon); } /** * * 火星坐标系 (GCJ-02) to 84 * * @param lon * @param lat * @return *火星转天地图 */ public static GPS gcj_To_Gps84(double lat, double lon) { GPS gps = transform(lat, lon); double lontitude = lon * 2 - gps.getLon(); double latitude = lat * 2 - gps.getLat(); return new GPS(latitude, lontitude); } /** * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标 *火星转百度 * @param gg_lat * @param gg_lon */ public static GPS gcj02_To_Bd09(double gg_lat, double gg_lon) { double x = gg_lon, y = gg_lat; double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * pi); double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * pi); double bd_lon = z * Math.cos(theta) + 0.0065; double bd_lat = z * Math.sin(theta) + 0.006; return new GPS(bd_lat, bd_lon); } /** * * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 * * 将 BD-09 坐标转换成GCJ-02 坐标 * * @param * 百度转火星 * * bd_lat * @param bd_lon * @return */ public static GPS bd09_To_Gcj02(double bd_lat, double bd_lon) { double x = bd_lon - 0.0065, y = bd_lat - 0.006; double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * pi); double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * pi); double gg_lon = z * Math.cos(theta); double gg_lat = z * Math.sin(theta); return new GPS(gg_lat, gg_lon); } /** * (BD-09)-->84 * 百度转天地图 * * @param bd_lat * @param bd_lon * @return */ public static GPS bd09_To_Gps84(double bd_lat, double bd_lon) { GPS gcj02 = bd09_To_Gcj02(bd_lat, bd_lon); GPS map84 = gcj_To_Gps84(gcj02.getLat(), gcj02.getLon()); return map84; } /** * is or not outOfChina * @param lat * @param lon * @return */ public static boolean outOfChina(double lat, double lon) { if (lon < 72.004 || lon > 137.8347){ return true;} if (lat < 0.8293 || lat > 55.8271){ return true;} return false; } public static GPS transform(double lat, double lon) { if (outOfChina(lat, lon)) { return new GPS(lat, lon); } double dLat = transformLat(lon - 105.0, lat - 35.0); double dLon = transformLon(lon - 105.0, lat - 35.0); double radLat = lat / 180.0 * pi; double magic = Math.sin(radLat); magic = 1 - ee * magic * magic; double sqrtMagic = Math.sqrt(magic); dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi); double mgLat = lat + dLat; double mgLon = lon + dLon; return new GPS(mgLat, mgLon); } public static double transformLat(double x, double y) { double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * Math.sqrt(Math.abs(x)); ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0; ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0; return ret; } public static double transformLon(double x, double y) { double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * Math.sqrt(Math.abs(x)); ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0; ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0; ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0; return ret; } }
2024-04-12 11:25:41 2KB java工具类
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考试类精品--立志在线学习系统,是基于java+vue开发的在线教育平台,将开发PC、小程序、手机端,集成RABC权
2024-04-11 17:11:39 488KB
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