C#数字+字母生成递增号

上传者: charles00ok1318 | 上传时间: 2019-12-21 19:32:40 | 文件大小: 69KB | 文件类型: zip
C#
C#数字+字母生成递增号,其中支持位数没有限制,2位、3位、4位、5位、6位等等,都可以,还有可以区分大小写,规则如下:例如4位数字+字母混合递增,先按照数字递增,然后按照字符递增

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评论信息

  • mikedongqd :
    不错,思路好
    2021-10-23
  • qq_37706680 :
    您好,您这个到0009Z就会出错,请问一下我到00009后自动0000A,OOOOZ,(i,O,不要)
    2020-12-26
  • qq_37706680 :
    您好,您这个到0009Z就会出错,请问一下我到00009后自动0000A,OOOOZ,(i,O,不要)
    2020-12-26
  • shibingzheng1208 :
    不错,可以作为参考
    2019-08-20
  • 代码如诗. :
    不错,可以作为参考
    2019-08-20
  • cdc8596 :
    很好,很不错的一个方法,可以参考
    2019-03-11
  • 奇点码农 :
    很好,很不错的一个方法,可以参考
    2019-03-11
  • hjnicholas :
    还行,可以作为参考
    2019-01-10
  • Jane.Hoo :
    还行,可以作为参考
    2019-01-10

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