看到一个不错的c++实现的md5算法
class MD5
{
public:
typedef unsigned int size_type; // must be 32bit
MD5();
MD5(const std::string& text);
void update(const unsigned char *buf, size_type length);
void update(const char *buf, size_type length);
MD5& finalize();
std::string hexdigest() const;
friend std::ostream& operator<<(std::ostream&, MD5 md5);
private:
void init();
typedef unsigned char uint1; // 8bit
typedef unsigned int uint4; // 32bit
enum {blocksize = 64}; // VC6 won't eat a const static int here
void transform(const uint1 block[blocksize]);
static void decode(uint4 output[], const uint1 input[], size_type len);
static void encode(uint1 output[], const uint4 input[], size_type len);
bool finalized;
uint1 buffer[blocksize]; // bytes that didn't fit in last 64 byte chunk
uint4 count[2]; // 64bit counter for number of bits (lo, hi)
uint4 state[4]; // digest so far
uint1 digest[16]; // the result
// low level logic operations
static inline uint4 F(uint4 x, uint4 y, uint4 z);
static inline uint4 G(uint4 x, uint4 y, uint4 z);
static inline uint4 H(uint4 x, uint4 y, uint4 z);
static inline uint4 I(uint4 x, uint4 y, uint4 z);
static inline uint4 rotate_left(uint4 x, int n);
static inline void FF(uint4 &a, uint4 b, uint4 c, uint4 d, uint4 x, uint4 s, uint4 ac);
static inline void GG(uint4 &a, uint4 b, uint4 c, uint4 d, uint4 x, uint4 s, uint4 ac);
static inline void HH(uint4 &a, uint4 b, uint4 c, uint4 d, uint4 x, uint4 s, uint4 ac);
static inline void II(uint4 &a, uint4 b, uint4 c, uint4 d, uint4 x, uint4 s, uint4 ac);
};
std::string md5(const std::string &str);
2023-12-06 08:01:50
5KB
md5
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