Scratch汉诺塔创意编程源程序
汉若塔：由4-8个不同积木块和3根柱子组成
游戏规则：
1、一次只能移一个积木（柱子最上面）
2、积木只能在三个柱子上存放
3、任何时刻不允许大的压小的
案例完美的诠释了什么是汉诺塔游戏，非常生动形象的进行了展示
完整的视频可以查看：https://www.bilibili.com/video/BV11P411V7GX/?vd_source=ecba593ad849be62c0c7d642db53eaad
更多Scratch资源可以关注：https://blog.csdn.net/frank2102
2022-12-01 13:25:18
4.64MB
用VB编写的简单汉诺塔程序
Private Sub cmdStart_Click()
n = Int(Text1.Text)
ReDim Data(1 To n, 1 To 3)
For i = 1 To n
For j = 1 To 3
Data(i, j) = 0
Next j
Next i
For i = 1 To n
Data(i, 1) = i
Next i
ColNow = 1
SelNum = 0
Call ShowPic
End Sub
Private Sub Form_KeyDown(KeyCode As Integer, Shift As Integer)
Select Case KeyCode
Case vbKeyUp
If SelNum = 0 Then SelNum = Data(1, ColNow): Call Pop
Case vbKeyDown
If SelNum <> 0 Then
If Push = True Then SelNum = 0
If Data(n, 3) = n Then Call ShowPic: MsgBox "恭喜你通过！", vbOKOnly, "Pass"
End If
Case vbKeyLeft
ColNow = ColNow - 1
If ColNow < 1 Then ColNow = 1
Case vbKeyRight
ColNow = ColNow + 1
If ColNow > 3 Then ColNow = 3
End Select
Call ShowPic
End Sub
2022-09-28 12:44:11
11KB
1
无论是用何种语言实现汉诺塔问题，其求解问题的核心算法和步骤还是大致相同的，下面总结了分别用JAVA/Python/C++ 实现汉诺塔问题的求解过程的代码和显示效果，可以体会一下不同语言下求解汉诺塔问题风格，下面我们来一起看一下吧。
C++实现汉诺塔问题求解
#include
using namespace std;
void move(char start,char end)
{
cout<<"move"<<start<<"to"<<end<<endl;
}
void hanoi(int n,char first,char second,char third)
{
if(n==
2022-09-20 10:00:42
55KB
1
儿童编程源码Scratch趣味小游戏源码集合，Scratch汉诺塔游戏源码，Scratch火柴人大战游戏源码，Scratch华容道游戏源码等。6个scratch小游戏源码,scratch小游戏合集,适合小朋友自学。新颖、有趣的游戏制作。喜欢学习scratch编程的大儿童们也可以自行下载学习参考哦，对自己学习scratch编程帮助很大。
2022-09-16 19:07:02
2.75MB
1
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class HannoiWindow extends JFrame implements ActionListener{
Tower tower=null;
int amountOfDisc=3;
char []towerName={'A','B','C'};
JMenuBar bar;
JMenu menuGrade;
JMenuItem oneGradeItem,twoGradeItem,threeGradeItem;
JButton renew=null;
JButton autoButton=null;
JPanel center=new JPanel();
HannoiWindow(){
tower=new Tower(towerName);
tower.setAmountOfDisc(amountOfDisc);
tower.setMaxDiscWidth(120);
tower.setMinDiscWidth(50);
tower.setDiscHeight(16);
tower.putDiscOnTower();
add(tower,BorderLayout.CENTER);
bar=new JMenuBar();
menuGrade=new JMenu("选择级别");
oneGradeItem=new JMenuItem("初级");
twoGradeItem=new JMenuItem("中级");
threeGradeItem=new JMenuItem("高级");
menuGrade.add(oneGradeItem);
menuGrade.add(twoGradeItem);
menuGrade.add(threeGradeItem);
bar.add(menuGrade);
setJMenuBar(bar);
oneGradeItem.addActionListener(this);
twoGradeItem.addActionListener(this);
threeGradeItem.addActionListener(this);
renew=new JButton("重新开始");
renew.addActionListener(this);
autoButton=new JButton("自动演示");
autoButton.addActionListener(this);
JPanel north=new JPanel();
north.add(renew);
north.add(autoButton);
String mess="将全部盘子从"+towerName[0]+"座搬运到"+towerName[1]+
"座或"+towerName[2]+"座";
JLabel hintMess=new JLabel(mess,JLabel.CENTER);
north.add(hintMess);
add(north,BorderLayout.NORTH);
setResizable(false);
setVisible(true);
setBounds(60,60,460,410);
validate();
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
public void actionPerformed(ActionEvent e){
if(e.getSource()==oneGradeItem){
amountOfDisc=3;
tower.setAmountOfDisc(amountOfDisc);
tower.putDiscOnTower();
}
else if(e.getSource()==twoGradeItem){
amountOfDisc=4;
tower.setAmountOfDisc(amountOfDisc);
tower.putDiscOnTower();
}
else if(e.getSource()==threeGradeItem){
amountOfDisc=5;
tower.setAmountOfDisc(amountOfDisc);
tower.putDiscOnTower();
}
else if(e.getSource()==renew){
tower.setAmountOfDisc(amountOfDisc);
tower.putDiscOnTower();
}
else if(e.getSource()==autoButton){
tower.setAmountOfDisc(amountOfDisc);
tower.putDiscOnTower();
int x=this.getBounds().x+this.getBounds().width;
int y=this.getBounds().y;
tower.getAutoMoveDisc().setLocation(x,y);
tower.getAutoMoveDisc().setSize(280,this.getBounds().height);
tower.getAutoMoveDisc().setVisible(true);
}
validate();
}
public static void main(String args[]){
new HannoiWindow();
}
}
2022-06-29 14:58:39
3KB
1