适合初学者学习与实践的内容 虽然比较浅显 但对于刚接触编程的人非常有帮助
2022-06-08 22:59:54 578KB c/c++
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Linux-C编程(经 典)个人认为还行
2022-05-31 10:32:44 4.89MB Linux C 编程
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C语言编程之 Unix C编程问题精粹.doc
2022-05-24 19:01:51 38KB unix 文档资料 c语言 服务器
C语言动画设计打包下载 TC2.0下运行 适合大学生程序设计 代码基础,可以直接运行 也可以简单修改再作为作业上交
2022-05-24 11:04:19 6KB C语言 编程 动画 代码
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C语言课程结课项目作业,使用dev运行
2022-05-22 20:55:45 2KB c语言 c# 开发语言 后端
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# include # include # include # include char * month_str[]={"January","February","March","April","May","June","July","August","September","October","November","December"}; char * week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"}; void Time() //获取系统时间 { time_t t; struct tm *tp; static char *week[]={"一","二","三","四","五","六","日"}; t=time(NULL); tp=localtime(&t); printf("\t  ─────────────────────\n"); printf("\t\t 现在是:%d年%d月%d日",tp->tm_year+1900,tp->tm_mon+1,tp->tm_mday); printf(" %d:%d:%d ",tp->tm_hour,tp->tm_min,tp->tm_sec); printf("星期%s\n",week[(tp->tm_wday)-1]); printf("\t  ─────────────────────\n"); } int IsLeapYear(int year) //判断闰年 { if((year%4==0&&year0!=0)||(year%400==0)) return 1; else return 0; } int month_day(int year,int month) { int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31}; if(IsLeapYear(year)&&month==2) return 29; else return(mon_day[month-1]); } int DaySearch(int year,int month,int day) //判断哪一天
2022-05-19 19:18:44 8KB 万年历 c
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ARM汇编语言编程详解ARM汇编语言编程详解ARM汇编语言编程详解ARM汇编语言编程详解ARM汇编语言编程详解
2022-05-18 16:57:53 506KB ARM 汇编语言
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精通UNIX下C语言编程与项目实践+源代码+笔记
2022-05-17 15:08:02 53.66MB unix c
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拉格朗日插值方法C语言编程
2022-05-15 15:18:41 28KB 拉格朗日插值 C
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